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MathematicsHigh school

Normal distribution and standard deviation - the bell curve explained step by step

· 16 min read

In short

The normal distribution models values that crowd around a mean and thin out evenly on both sides - its graph is the bell curve. The mean μ says where the middle is, and the standard deviation σ says how spread out the values are. The share of values in a range is the area under the curve - about 68% lie within one σ of the mean, 95% within 2σ and 99.7% within 3σ.

Words to know

Mean (μ, x̄)
The sum of the values divided by how many there are - the centre of the data.
Standard deviation (σ)
How far the values typically are from the mean. It is the square root of the variance.
Variance (σ²)
The mean of the squared distances of the values from the mean.
Normal distribution N(μ, σ²)
A symmetric, bell-shaped distribution, set by its mean μ and its standard deviation σ.
z-score
How many standard deviations a value is from the mean - z = (x − μ)/σ.
Φ(z)
The area under the standard normal curve to the left of z - the probability P(Z < z).

What do you think?

A machine fills bags of flour. The mass of a bag follows a normal distribution with mean 10001000 g and standard deviation 55 g. About what share of the bags weigh more than 10051005 g?

The idea: most values sit close to the mean

A machine is set to fill bags with 10001000 g of flour. Weigh a thousand of its bags, and they will not all weigh exactly 10001000 g. Most will be close to it, some will be a little further off, and very few will be far off. Drawn as a histogram, the masses make a roughly symmetric hump - a bell.

The normal distribution is the mathematical model of that bell. It is set by just two numbers:

  • the mean μ\mu (the Greek letter mu) - where the middle of the bell is,
  • the standard deviation σ\sigma (sigma) - how far the values typically are from the mean. A small σ\sigma gives a narrow, tall bell, and a large σ\sigma a wide, low one.

The share of values in a range is the area under the curve over that range. The whole area under the curve is 11, that is, 100%.

Why does the bell turn up so often? Roughly speaking, the sum or the mean of many independent random values is approximately normal, whatever their own distribution - that is the central limit theorem. The normal distribution is also called the Gaussian distribution, after the mathematician Carl Friedrich Gauss.

From a histogram to the bell curve

Go through the animation step by step with the buttons or the arrow keys. The bars show the masses of 10001000 bags (simulated on a computer), and the coloured curve is the normal distribution that models them.

98099010001010102050100150200

1000 bags

Step 1 of 7
Steps of the animation. Arrow keys move between steps.

A machine fills bags of flour, and we have weighed 1000 of them. Each bar counts the bags in a 2.5 g range. Most bags weigh close to 1000 g, and the further from 1000 g, the fewer there are.

The curve does not match every bar exactly. It is a model: it describes the pattern, not every single bag. The more bags we weigh, the closer the histogram comes to the curve - try it in the lab below.

Try it yourself: μ, σ and the area under the curve

The sliders set the machine’s mean μ\mu and standard deviation σ\sigma, and a range from aa to bb. The shaded area is the probability that a bag’s mass falls in that range. Then weigh a few hundred bags and compare the share of them in that range with the area.

9709809901000101010201030
μ = 1000 g
σ = 5 g
a = 995 g
b = 1005 g
z for a
−1
z for b
1
area from a to b = P(a < X < b)
68.3%

bags weighed: 0

What to notice:

  • changing μ\mu only moves the curve - its shape stays the same,
  • a larger σ\sigma gives a wider, lower curve, because the area under it is always 11,
  • set aa and bb one σ\sigma either side of μ\mu (say μ=1000\mu = 1000, σ=4\sigma = 4, a=996a = 996 and b=1004b = 1004): the area is 68.3%, whatever μ\mu and σ\sigma are,
  • the area depends only on the z-scores of aa and bb,
  • the more bags you weigh, the closer the share of them from aa to bb comes to the area.

The definition

The mean and standard deviation of data. For the data x1,x2,…,xnx_1, x_2, \ldots, x_n the mean is

xˉ=x1+x2+…+xnn.\bar{x} = \frac{x_1 + x_2 + \ldots + x_n}{n}.

The variance is the mean of the squared distances from the mean, and the standard deviation is its square root:

σ2=(x1−xˉ)2+…+(xn−xˉ)2n\sigma^2 = \frac{(x_1 - \bar{x})^2 + \ldots + (x_n - \bar{x})^2}{n}
σ=σ2\sigma = \sqrt{\sigma^2}

We square the distances so that the ones below and above the mean do not cancel out. The square root brings the result back to the units of the data, such as grams. In statistics, the standard deviation of a sample is often worked out with n−1n - 1 instead of nn in the denominator; for large samples the difference is small.

The normal distribution. A random variable XX has the normal distribution with mean μ\mu and standard deviation σ\sigma, written N(μ,σ2)N(\mu, \sigma^2), when its probabilities are areas under the bell curve

f(x)=1σ2π e−(x−μ)22σ2.f(x) = \frac{1}{\sigma\sqrt{2\pi}}\, e^{-\frac{(x - \mu)^2}{2\sigma^2}}.

The curve is symmetric about x=μx = \mu and highest there. Its points of inflection, where the curve changes the way it bends, are at μ−σ\mu - \sigma and μ+σ\mu + \sigma. The whole area under it is 11. The probability that XX lies between aa and bb is the area under the curve from aa to bb. A single value has probability 00, so P(a<X<b)P(a < X < b) and P(a≤X≤b)P(a \le X \le b) are the same.

The 68-95-99.7 rule. For every normal distribution:

  • about 68.27% of the values lie within one σ\sigma of the mean, from μ−σ\mu - \sigma to μ+σ\mu + \sigma,
  • about 95.45% lie within 2σ2\sigma,
  • about 99.73% lie within 3σ3\sigma.

Standardising. The z-score z=x−μσz = \frac{x - \mu}{\sigma} says how many standard deviations xx is from the mean. If XX has the distribution N(μ,σ2)N(\mu, \sigma^2), then Z=X−μσZ = \frac{X - \mu}{\sigma} has the standard normal distribution N(0,1)N(0, 1). Its areas Φ(z)=P(Z<z)\Phi(z) = P(Z < z) are in tables and on calculators:

zz Φ(z)\Phi(z)
0.50.5 0.69150.6915
11 0.84130.8413
1.51.5 0.93320.9332
1.61.6 0.94520.9452
22 0.97720.9772
33 0.99870.9987

Many tables list only z≥0z \ge 0. For a negative zz, use the symmetry of the curve:

Φ(−z)=1−Φ(z)\Phi(-z) = 1 - \Phi(z)

For a range from aa to bb, with zaz_a and zbz_b the z-scores of its ends:

P(a<X<b)=Φ(zb)−Φ(za)P(a < X < b) = \Phi(z_b) - \Phi(z_a)

Example 1: the standard deviation of five numbers

Five students timed how long a puzzle took them, in minutes: 44, 66, 77, 88 and 1010. Find the mean and the standard deviation of these times.

Step 1. Work out the mean

We add up the five times and divide by 55.

xˉ=4+6+7+8+105=355=7\begin{aligned} \bar{x} &= \frac{4 + 6 + 7 + 8 + 10}{5} \\ &= \frac{35}{5} \\ &= \boxed{7} \end{aligned}

Step 2. Subtract the mean from each time

We take 77 away from each time; the times below the mean give negative differences.

4−7=−36−7=−17−7=08−7=110−7=3\begin{aligned} 4 - 7 &= -3 \\ 6 - 7 &= -1 \\ 7 - 7 &= 0 \\ 8 - 7 &= 1 \\ 10 - 7 &= 3 \end{aligned}

Step 3. Square the differences and add them up

Squaring gets rid of the minus signs.

(−3)2+(−1)2+02+12+32=9+1+0+1+9=20\begin{aligned} &(-3)^2 + (-1)^2 + 0^2 + 1^2 + 3^2 \\ &= 9 + 1 + 0 + 1 + 9 \\ &= 20 \end{aligned}

Step 4. Divide by the number of values

The variance is the mean of the squared distances.

σ2=205=4\sigma^2 = \frac{20}{5} = \boxed{4}

Step 5. Take the square root

The standard deviation is the square root of the variance.

σ=4=2\sigma = \sqrt{4} = 2

Answer

xˉ=7\bar{x} = 7 minutes and σ=2\sigma = 2 minutes. The times are typically about 22 minutes away from the mean.

Example 2: the share of light bags

The mass of a bag of flour follows a normal distribution with mean μ=1000\mu = 1000 g and standard deviation σ=5\sigma = 5 g. What share of the bags weigh less than 992992 g?

Step 1. Standardise the mass

We work out how many standard deviations 992992 g is from the mean.

z=992−10005=−85=−1.6\begin{aligned} z &= \frac{992 - 1000}{5} \\ &= \frac{-8}{5} \\ &= \boxed{-1.6} \end{aligned}

Step 2. Write the share using Φ

A mass below 992992 g has a z-score below −1.6-1.6.

P(X<992)=Φ(−1.6)P(X < 992) = \Phi(-1.6)

Step 3. Use the symmetry of the curve

The table lists only positive zz, so we use Φ(−z)=1−Φ(z)\Phi(-z) = 1 - \Phi(z).

Φ(−1.6)=1−Φ(1.6)\Phi(-1.6) = 1 - \Phi(1.6)

Step 4. Read the table and subtract

The table gives Φ(1.6)=0.9452\Phi(1.6) = 0.9452.

1−Φ(1.6)=1−0.9452=0.0548\begin{aligned} 1 - \Phi(1.6) &= 1 - 0.9452 \\ &= 0.0548 \end{aligned}

Answer

P(X<992)≈0.0548P(X < 992) \approx 0.0548. About 5.5% of the bags weigh less than 992992 g - roughly 5555 in every 10001000.

Your turn

The heights of young tomato plants in a greenhouse follow a normal distribution with mean 6060 cm and standard deviation 1212 cm. What share of the plants are between 5454 cm and 7878 cm tall?

Hintshow

Work out the z-scores of 5454 and 7878. The share is Φ(zb)−Φ(za)\Phi(z_b) - \Phi(z_a), and for a negative zz use Φ(−z)=1−Φ(z)\Phi(-z) = 1 - \Phi(z). From the table: Φ(0.5)=0.6915\Phi(0.5) = 0.6915 and Φ(1.5)=0.9332\Phi(1.5) = 0.9332.

Solutiontry it on your own first

Step 1. Standardise both ends

We work out the z-scores of 5454 cm and 7878 cm.

za=54−6012=−0.5zb=78−6012=1.5\begin{aligned} z_a &= \frac{54 - 60}{12} = -0.5 \\ z_b &= \frac{78 - 60}{12} = 1.5 \end{aligned}

Step 2. Write the share as a difference

The share is the area to the left of zbz_b minus the area to the left of zaz_a.

P=Φ(1.5)−Φ(−0.5)P = \Phi(1.5) - \Phi(-0.5)

Step 3. Use the symmetry of the curve

The table lists only positive zz, so we turn Φ(−0.5)\Phi(-0.5) into a value from the table.

Φ(−0.5)=1−Φ(0.5)=1−0.6915=0.3085\begin{aligned} \Phi(-0.5) &= 1 - \Phi(0.5) \\ &= 1 - 0.6915 \\ &= \boxed{0.3085} \end{aligned}

Step 4. Subtract

We take Φ(1.5)=0.9332\Phi(1.5) = 0.9332 from the table and subtract the result of step 3.

P=0.9332−0.3085=0.6247\begin{aligned} P &= 0.9332 - 0.3085 \\ &= 0.6247 \end{aligned}

Answer

P(54<X<78)≈0.6247P(54 < X < 78) \approx 0.6247. About 62.5% of the plants are between 5454 cm and 7878 cm tall.

Common mistakes

  • Looking up xx instead of zz. The table is for the standard normal distribution, so standardise first. For 992992 g with μ=1000\mu = 1000 g and σ=5\sigma = 5 g, work with z=−1.6z = -1.6, not with 992992.
  • Forgetting the “1 −”. Φ(z)\Phi(z) is the area to the left of zz. For “more than” you need the area to the right: P(Z>z)=1−Φ(z)P(Z > z) = 1 - \Phi(z). For example, P(Z>1)=1−0.8413=0.1587P(Z > 1) = 1 - 0.8413 = 0.1587.
  • Mixing up σ\sigma and σ2\sigma^2. Books write the normal distribution either as N(μ,σ2)N(\mu, \sigma^2) or as N(μ,σ)N(\mu, \sigma). In N(10,16)N(10, 16), written the first way, the standard deviation is 16=4\sqrt{16} = 4, not 1616. Check which way your book writes it.
  • Using 68-95-99.7 for any data. The rule holds for normal distributions. For other shapes the shares are different: in a uniform distribution, where every value in an interval is equally likely, only about 58% of the values lie within one σ\sigma of the mean.
  • “A larger σ makes the curve taller.” It is the other way round. The area under the curve is always 11, so a wider curve must be lower: the height of its peak is 1σ2π\frac{1}{\sigma\sqrt{2\pi}}.

In exams and at university

In England, the normal distribution is part of A-level Mathematics, though not of the shorter AS course. Students use it as a model and find probabilities from it, and they link it to histograms, the mean, the standard deviation and the points of inflection. They must be able to get probabilities from statistical distributions such as this one on a calculator. A-level writes the distribution as N(μ,σ2)N(\mu, \sigma^2), with the variance as the second number. Students also test hypotheses about the mean of a normal distribution. The standard deviation itself comes earlier, already in the AS content: students calculate and interpret it, including from summary statistics.

In the United States, the normal distribution is a topic of AP Statistics, a course equivalent to a one-semester introductory college course in statistics.

At university, the normal distribution is a standard topic of a first course in statistics. In the open textbook OpenIntro Statistics it comes after the chapters on summarising data and on probability. The next chapter, on the foundations of inference, builds on it and introduces the central limit theorem.

Check yourself

Test yourself

A normal distribution has μ=50\mu = 50 and σ=4\sigma = 4. Between which two values does about 95% of the distribution lie?

What happens to the normal curve when σ\sigma grows and μ\mu stays the same?

XX has the normal distribution with μ=20\mu = 20 and σ=4\sigma = 4. What is the z-score of x=26x = 26?

The table gives Φ(1)=0.8413\Phi(1) = 0.8413. What is P(Z>1)P(Z > 1)?

What is the standard deviation of the data 33, 33, 77, 77?

Flashcards for review

Flip a card and say whether you knew the answer. The ones you did not know come back at the end of the deck. Why it pays to come back to them in a few days is explained in the guide Spaced repetition.

Flashcards

  1. What do μ\mu and σ\sigma tell you about a normal curve?

    μ\mu is where its middle and its peak are. σ\sigma says how spread out the values are: a larger σ\sigma gives a wider, lower curve.
  2. How do you work out the standard deviation of data?

    Find the mean, square each value’s distance from it, and take the mean of those squares - that is the variance. The standard deviation is its square root.
  3. What does the 68-95-99.7 rule say?

    In a normal distribution about 68% of the values lie within one σ\sigma of the mean, about 95% within 2σ2\sigma and about 99.7% within 3σ3\sigma.
  4. What is the z-score of a value xx?

    z=x−μσz = \frac{x - \mu}{\sigma} - how many standard deviations xx is from the mean.
  5. What does Φ(z)\Phi(z) mean?

    The area under the standard normal curve to the left of zz, that is P(Z<z)P(Z < z).
  6. How do you find Φ(−z)\Phi(-z) from a table?

    Φ(−z)=1−Φ(z)\Phi(-z) = 1 - \Phi(z) - the curve is symmetric about 00.
  7. How do you find P(a<X<b)P(a < X < b) for a normal XX?

    Standardise both ends and subtract: Φ(zb)−Φ(za)\Phi(z_b) - \Phi(z_a).
  8. What is the whole area under a normal curve?

    11, that is 100%. That is why a curve with a larger σ\sigma is lower.
  9. Where are the points of inflection of a normal curve?

    At μ−σ\mu - \sigma and μ+σ\mu + \sigma.

Sources

We checked the facts on this page against these sources. All of them may be reused freely: they carry an open licence or are not covered by copyright.

  1. OpenIntro (Diez, Çetinkaya-Rundel, Barr) - OpenIntro Statistics, 2.1 Examining numerical data and 4.1 Normal distribution (variance and the n − 1 version; the mean shifts the curve and σ stretches it; z = (x − μ)/σ; the 68-95-99.7 rule; the order of the chapters) · CC BY-SA 3.0
  2. David M. Lane - Online Statistics Education, Measures of Variability (variance as the average squared deviation from the mean; σ² with N, s² with N − 1; the standard deviation is its square root) · public domain
  3. David M. Lane - Online Statistics Education, Introduction to Normal Distributions (symmetric, area 1, 68% within one standard deviation and about 95% within two; the Gaussian curve) · public domain
  4. David M. Lane - Online Statistics Education, Distributions (for a continuous variable an exact value has probability 0; probability is the area between two points) · public domain
  5. NIST/SEMATECH e-Handbook of Statistical Methods - 1.3.6.6.1 Normal Distribution (the density formula; the standard normal distribution has μ = 0 and σ = 1; the central limit theorem) · public domain
  6. NIST/SEMATECH e-Handbook of Statistical Methods - 1.3.6.6.2 Uniform Distribution (standard deviation √((B − A)²/12)) · public domain
  7. Kyle Siegrist - Probability, Mathematical Statistics, and Stochastic Processes, 5.6 The Normal Distribution (symmetric about μ, highest at μ, points of inflection at μ ± σ; Z = (X − μ)/σ; Φ(−z) = 1 − Φ(z); named after Gauss) · CC BY 2.0
  8. Danielle Navarro - Learning Statistics with R, 9.5 The Normal Distribution (μ shifts the curve; a larger σ makes it wider and its peak lower; total area 1; 68.3%, 95.4% and 99.7%) · CC BY-SA 4.0
  9. Rachel Webb - Mostly Harmless Statistics, 3.2 Measures of Spread (the population σ divides by N, the sample s by n − 1) · CC BY-SA 4.0
  10. Rachel Webb - Mostly Harmless Statistics, 6.4 Normal Distribution (X ~ N(μ, σ); total area 1; the empirical rule 68-95-99.7; z = (x − μ)/σ) · CC BY-SA 4.0
  11. Wikipedia - Normal distribution (N(μ, σ²); points of inflection at μ ± σ; Φ(−x) = 1 − Φ(x); standardising) · CC BY-SA 4.0
  12. Wikipedia - 68–95–99.7 rule (68.27%, 95.45% and 99.73%) · CC BY-SA 4.0
  13. Wikipedia - Standard deviation (dividing by n or by n − 1; for very large samples the difference is small) · CC BY-SA 4.0
  14. Wikipedia - AP Statistics (equivalent to a one-semester introductory college course in statistics; tables for the normal distribution are given in the exam) · CC BY-SA 4.0

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